Find the volume enclosed by the cylinder `y^2=x` and `y=x^2` Cut off by the planes z = 0, x+y+z=2.
The solid is bounded by the parabolas `y^2=x`, `y=x^2` in the x y plane.
In x-y-z plane x+y+z =2 is top base.
The volume between this curves is given by ,
V = ∫∫𝒛 𝒅𝒙 𝒅𝒚= ∫∫(𝟐−𝒙−𝒚)𝒅𝒙𝒅𝒚
From the diagram we can conclude that the intersection point of both Parabolas are (0,0),(1,1).