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Find the Vector Equation of the Line Passing Through (1, 2, 3) and Parallel to the Planes Vecr = (Hati - Hatj + 2hatk) = 5`And Vecr.(3hati + Hatj + Hatk) = 6 - CBSE (Commerce) Class 12 - Mathematics

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Question

Find the vector equation of the line passing through (1, 2, 3) and parallel to the planes `vecr = (hati - hatj + 2hatk)  = 5`and `vecr.(3hati + hatj + hatk) = 6`

Solution

Let the required line be parallel to vector `vecb` given by,

`vecb = b_1hati + b_2hatj + b_3hatk`

The position vector of the point (1, 2, 3) is `veca = hati + 2hatj + 3hatk`

The equation of line passing through (1, 2, 3) and parallel to `vecb`is given by,

This is the equation of the required line.

  Is there an error in this question or solution?

APPEARS IN

 NCERT Solution for Mathematics Textbook for Class 12 (2018 to Current)
Chapter 11: Three Dimensional Geometry
Q: 19 | Page no. 499
Solution Find the Vector Equation of the Line Passing Through (1, 2, 3) and Parallel to the Planes Vecr = (Hati - Hatj + 2hatk) = 5`And Vecr.(3hati + Hatj + Hatk) = 6 Concept: Plane - Equation of a Plane Perpendicular to a Given Vector and Passing Through a Given Point.
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