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Find the values of y for which the distance between the points P (2, - 3) and Q (10, y) is 10 units - Mathematics

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 Find the values of y for which the distance between the points P (2, - 3) and Q (10, y) is 10 units

 

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Solution

It is given that the distance between (2, −3) and (10, y) is 10.

Therefore

`sqrt((2-10)^2+(-3-y)^2) = 10`

`sqrt((-8)^2+(3+y)^2) = 10`

64 + (y +3)2 = 100

(y+3)2 = 36

y+3 = ±6

y+3=6 or y+3 = -6

Therefore y = 3 or -9

Concept: Distance Formula
  Is there an error in this question or solution?

APPEARS IN

NCERT Class 10 Maths
Chapter 7 Coordinate Geometry
Exercise 7.1 | Q 8 | Page 161

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