Answer 1

The given quadric equation is 3x² - 5x + 2k = 0, and roots are real and equal

Then find the value of k.

Here, a = 3, b = -5 and c = 2k

As we know that D = b² - 4ac

Putting the value of a = 3, b = -5 and c = 2k

= (-5)² - 4 x (3) x (2k)

= 25 - 24k

The given equation will have real and equal roots, if D = 0

Thus,

25 - 24k = 0

24k = 25

k = 25/24

Therefore, the value of k = 25/24.