# Find the Values the Following Correct to Three Places of Decimals, It Being Given that Sqrt2 = 1.4142, Sqrt3 = 1.732, Sqrt5 = 2.2360, Sqrt6 = 2.4495 and Sqrt10 = 3.162 - Mathematics

Find the values the following correct to three places of decimals, it being given that sqrt2 = 1.4142, sqrt3 = 1.732, sqrt5 = 2.2360, sqrt6 = 2.4495 and sqrt10 = 3.162

(1 + sqrt2)/(3 - 2sqrt2)

#### Solution

We know that rationalization factor for 3 - 2sqrt2 is 3 + 2sqrt2. We will multiply numerator and denominator of the given expression (1 + sqrt2)/(3 - 2sqrt2) by 3 + 2sqrt2 to get

(1 + sqrt2)/(3 - 2sqrt2) xx (3 + 2sqrt2)/(3 + 2sqrt2) = (3 + 2 xx sqrt2 + 3 xx sqrt2 + 2 xx (sqrt2)^2)/((3)^2 - (2sqrt2)^2)

= (3 + 2sqrt2 + 3sqrt2 + 4)/(9 - 8)

= (7 + 5sqrt2)/1

Putting te value of sqrt2 we get

7 + 5sqrt2 = 7 + 5(1.4142)

= 7 + 7.071

= 14.071

Hence the given expression  is simplified to 14.071

Concept: Operations on Real Numbers
Is there an error in this question or solution?

#### APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 3 Rationalisation
Exercise 3.2 | Q 8.2 | Page 15

Share