Answer 1

The given system of equations may be written as

2x - 3y - 7 = 0

(a + b)x - (a + b - 3)y - 4a + b = 0

It is of the form

`a_1x + b_1y + c_1 = 0`

`a_2x + b_2y + c_2 = 0`

Where `a_1 = 2, b_1 = -3,c_1 = -7`

And `a_2 = a + b, b_2 = -(a + b - 3), c_2 = -(4a + b) `

The given system of equations will have infinite number of solutions, if

`a_1/a_2 - b_1/b_2 = c_1/c_2`

`=> 2/(a + b) = (-3)/(-(a + b - 3)) = (-7)/(-(4a + b))`

`=> 2(a + b -3) = 3(a + b) and  3(4a + b) = 7(a + b - 3)`

=> -6 = 3a - 2a + 3b - 2b  and 12a - 7a + 3b - 7b = 21

=> -6 = a + b and 5a - 4b = -21

Now

a + b = -6

=> a = -6 - b

Substituting the value of a i n 5a - 4b = -2 we get

5(-b - 6 )- 4b = -21

=> -5b - 30 - 4b = -21

=> -9b = -21 + 30

=> -9b = 9

`=> b = 9/(-9) = -1`

Putting b = -1 in a = -b-6 we get

a = -(-1) - 6 = 1 - 6 = -5

Hence, the given system of equations will have infinitely many solutions,

if a = -5 and b = -1