Find the value of x in the following:
`5^(2x+3)=1`
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Solution
Given `5^(2x+3)=1`
`5^(2x+3)=5^0`
On equating the exponents we get
⇒ 2x + 3 = 0
⇒ 2x = -3
`rArr x = (-3)/2`
Concept: Laws of Exponents for Real Numbers
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