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# Find the Value of X in the Following: (3/5)^X(5/3)^(2x)=125/27 - CBSE Class 9 - Mathematics

ConceptLaws of Exponents for Real Numbers

#### Question

Find the value of x in the following:

(3/5)^x(5/3)^(2x)=125/27

#### Solution

Given (3/5)^x(5/3)^(2x)=125/27

3^x/5^x xx5^(2x)/3^(2x)=125/27

3^x/3^(2x)xx5^(2x)/5^x=125/27

5^(2x-x)/3^(2x-x)=125/27

5^(2x-x)/3^(2x-x)=5^3/3^3

(5/3)^(2x-x)=(5/3)^3

Comparing exponents we get

2x - x = 3

x = 3

Hence, the value of x = 3.

Is there an error in this question or solution?

#### APPEARS IN

RD Sharma Solution for Mathematics for Class 9 by R D Sharma (2018-19 Session) (2018 to Current)
Chapter 2: Exponents of Real Numbers
Ex. 2.20 | Q: 10.3 | Page no. 26

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Solution Find the Value of X in the Following: (3/5)^X(5/3)^(2x)=125/27 Concept: Laws of Exponents for Real Numbers.
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