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Find the Value to Three Places of Decimals of the Following. It is Given that Sqrt2 = 1.414, Sqrt3 = 1.732, Sqrt5 = 2.236and `Sqrt10 = 3.162` `(Sqrt5 + 1)/Sqrt2` - Mathematics

Find the value to three places of decimals of the following. It is given that

`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`

`(sqrt5 + 1)/sqrt2`

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Solution

We know that rationalization factor of the denominator is `sqrt2`.We will multiply numerator and denominator of the given expression `(sqrt5 + 1)/sqrt2` by `sqrt2` to get

`(sqrt5 + 1)/sqrt2 xx sqrt2/sqrt2 = (sqrt10 + sqrt2)/(sqrt2 xx sqrt2)`

`= (sqrt10 + sqrt2)/2`

`= (3.162 + 1.414)/2`

= 4.576/2

= 2.288

The value of expression 2.288 can be round off to three decimal places as 2.288.

Hence the given expression is simplified to 2.288.

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APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 3 Rationalisation
Exercise 3.2 | Q 2.3 | Page 14
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