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When a 12 V battery is connected across an unknown resistor, there is a current of 2.5 mA in the circuit. Find the value of the resistance of the resistor.

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#### Solution

Resistance (*R*) of a resistor is given by Ohm’s law as,*V*= *IR**R*= *V*/*I*

Where,

Potential difference, *V*= 12 *V*

Current in the circuit, *I*= 2.5 mA = 2.5 x 10^{-3} A

`R=12/(2.5xx 10^-3)=-4.8xx10^3Omega=4.8 kOmega`

Therefore, the resistance of the resistor is 4.8 kΩ

Concept: Ohm's Law (V = IR)

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