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Find the Value of K for Which the System Kx + 2y = 5 3x + Y = 1 Has (I) a Unique Solution, and (Ii) No Solution. - Mathematics

Find the value of k for which the system
kx + 2y = 5
3x + y = 1
has (i) a unique solution, and (ii) no solution.

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Solution

The given system of equation may be written as

kx + 2y - 5 = 0

3x + y - 1 = 0

It is of the form

`a_1x + b_1y + c_1 = 0`

`a_2x + b_2y + c_2 = 0`

Where `a_1 = k, b_1 = 2, c_1 = -5`

And `a_2 = 3, b_2 = 1, c_2 = -1`

Where, `a_1 = k, b_1 = 2, c_1 = -5`

And `a_2 = 3, b_2 = 1, c_2 = -1`

1) The given system will have a unique solution, if

`a_1/a_2 != b_1/b_2`

`=> k/3 != 2/1`

`=> k != 6`

So, the given system of equations will have a unique solution, if `k != 6`

2) The given system will have no solution, if

`a_1/a_2 - b_1/b_2 != c_1/c_2`

we have

`b_1/b_2 = 2/1 and c_1/c_2 = (-5)/(-1) = 5/1`

Clearly `b_1/b_2 != c_1/c_2`

So, the given system of equations will have no solution, if

`a_1/a_2 = b_1/b_2`

`=> k/3 = 2/1`

=> k = 6

Hence, the given system of equations will have no solution if k = 6

  Is there an error in this question or solution?
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APPEARS IN

RD Sharma Class 10 Maths
Chapter 3 Pair of Linear Equations in Two Variables
Exercise 3.5 | Q 5 | Page 73
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