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Find the value of k, if x – 1 is a factor of p(x) in the following case:- p(x) = kx^2 - √2x +1 - Mathematics

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Find the value of k, if x – 1 is a factor of p(x) in the following case:- `p(x) = kx^2 - sqrt2x +1`

 

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Solution

If x − 1 is a factor of polynomial p(x), then p(1) must be 0.

`p(x) = kx^2 - sqrt2x +1`

p(1) = 0

`⇒ k(1)^2 - sqrt2(1) + 1 = 0`

`⇒ k - sqrt2 + 1`

`⇒ k = sqrt2 - 1`

Therefore, the value of k is `sqrt2 -1" ."`

 

Concept: Factorising the Quadratic Polynomial (Trinomial) of the type ax2 + bx + c, a ≠ 0.
  Is there an error in this question or solution?

APPEARS IN

NCERT Class 9 Maths
Chapter 2 Polynomials
Exercise 2.4 | Q 3.3 | Page 44
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