Question
Find the value of k, if x – 1 is a factor of p(x) in the following case:- `p(x) = kx^2 - sqrt2x +1`
Solution
If x − 1 is a factor of polynomial p(x), then p(1) must be 0.
`p(x) = kx^2 - sqrt2x +1`
p(1) = 0
`⇒ k(1)^2 - sqrt2(1) + 1 = 0`
`⇒ k - sqrt2 + 1`
`⇒ k = sqrt2 - 1`
Therefore, the value of k is `sqrt2 -1" ."`
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Solution Find the value of k, if x – 1 is a factor of p(x) in the following case:- p(x) = kx^2 - √2x +1 Concept: Factorisation of Polynomials.
