# Find the value of k, if x – 1 is a factor of p(x) in the following case:- p(x) = 2x^2+kx+√2 - Mathematics

Find the value of k, if x – 1 is a factor of p(x) in the following case:-

p(x) = 2x^2+kx+sqrt2

#### Solution

If x − 1 is a factor of polynomial p(x), then p(1) must be 0.

p(x) = 2x^2+kx+sqrt2

p(1) = 0

⇒ 2(1)^2 + k(1) + sqrt2 = 0

⇒ 2 + k + sqrt2 = 0

⇒ k = -2 -sqrt2 = -(2+sqrt2)

Therefore, the value of k is -(2+sqrt2)" ."

Concept: Factorising the Quadratic Polynomial (Trinomial) of the type ax2 + bx + c, a ≠ 0.
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#### APPEARS IN

NCERT Class 9 Maths
Chapter 2 Polynomials
Exercise 2.4 | Q 3.2 | Page 44