Advertisement Remove all ads

Find the value of k, if x – 1 is a factor of p(x) in the following case:- p(x) = 2x^2+kx+√2 - Mathematics

Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads

Find the value of k, if x – 1 is a factor of p(x) in the following case:-

`p(x) = 2x^2+kx+sqrt2`

 

Advertisement Remove all ads

Solution

If x − 1 is a factor of polynomial p(x), then p(1) must be 0.

`p(x) = 2x^2+kx+sqrt2`

p(1) = 0

`⇒ 2(1)^2 + k(1) + sqrt2 = 0`

`⇒ 2 + k + sqrt2 = 0`

`⇒ k = -2 -sqrt2 = -(2+sqrt2)`

Therefore, the value of k is `-(2+sqrt2)" ."`

 

Concept: Factorising the Quadratic Polynomial (Trinomial) of the type ax2 + bx + c, a ≠ 0.
  Is there an error in this question or solution?

APPEARS IN

NCERT Class 9 Maths
Chapter 2 Polynomials
Exercise 2.4 | Q 3.2 | Page 44
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×