Advertisement Remove all ads

Find the value of k, if the points A(7, −2), B (5, 1) and C (3, 2k) are collinear. - Mathematics

Answer in Brief

Find the value of k, if the points A(7, −2), B (5, 1) and (3, 2k) are collinear.

 
Advertisement Remove all ads

Solution

The formula for the area ‘A’ encompassed by three points(x1,y1) , (x2 , y2)  and (x3 , y3)   is given by the formula,

\[∆ = \frac{1}{2}\left| \left( x_1 y_2 + x_2 y_3 + x_3 y_1 \right) - \left( x_2 y_1 + x_3 y_2 + x_1 y_3 \right) \right|\]

If three points are collinear the area encompassed by them is equal to 0.

The three given points are A(7, −2), B(5, 1) and C(3, 2k). It is also said that they are collinear and hence the area enclosed by them should be 0.

\[∆ = \frac{1}{2}\left| \left( 7 \times 1 + 5 \times 2k + 3 \times - 2 \right) - \left( 5 \times - 2 + 3 \times 1 + 7 \times 2k \right) \right|\]

\[ 0 = \frac{1}{2}\left| \left( 7 + 10k - 6 \right) - \left( - 10 + 3 + 14k \right) \right|\]

\[ 0 = \frac{1}{2}\left| - 4k + 8 \right|\]

\[ 0 = - 4k + 8\]

\[ k = 2\]

 

Hence the value of ‘k’ for which the given points are collinear is k = 2 .

 

 
  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

RD Sharma Class 10 Maths
Chapter 6 Co-Ordinate Geometry
Exercise 6.5 | Q 16 | Page 54
Advertisement Remove all ads

Video TutorialsVIEW ALL [2]

Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×