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# Find the Value of K, If the Point P (0, 2) is Equidistant from (3, K) and (K, 5). - CBSE Class 10 - Mathematics

ConceptConcepts of Coordinate Geometry

#### Question

Find the value of k, if the point P (0, 2) is equidistant from (3, k) and (k, 5).

#### Solution

The distance d between two points (x_1,y_1) and (x_2, y_2) is given by the formula

d = sqrt((x_1 - x_2)^2 + (y_1 - y_2)^2)

It is said that P(0,2) is equidistant from both A(3,k) and B(k,5).

So, using the distance formula for both these pairs of points we have

AP =sqrt((3)^2 + (k - 2)^2)

BP = sqrt((k)^2 + (3)^2)

Now since both these distances are given to be the same, let us equate both.

AP = Bp

sqrt((3)^2 + (k -2)^2) = sqrt((k)^2 + (3)^2)

Squaring on both sides we have,

(3)^2 + (k - 2)^2 = (k)^2 + (3)^2

9 + k^2 + 4 - 4k = k^2 + 9

4k = 4

k = 1

Hence the value of ‘k’ for which the point ‘P’ is equidistant from the other two given points is k = 1

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Solution Find the Value of K, If the Point P (0, 2) is Equidistant from (3, K) and (K, 5). Concept: Concepts of Coordinate Geometry.
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