Find the value of (3−1 + 4−1 + 5−1)0
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Solution
(3−1 + 4−1 + 5−1)0 = `(1/3 + 1/4 + 1/5)^0` `" "(a^(-m = 1/ a^m))`
= 1 (a0 = 1)
Concept: Powers with Negative Exponents
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