Advertisement Remove all ads
Find the value of (3−1 + 4−1 + 5−1)0
Advertisement Remove all ads
Solution
(3−1 + 4−1 + 5−1)0 = `(1/3 + 1/4 + 1/5)^0` `" "(a^(-m = 1/ a^m))`
= 1 (a0 = 1)
Concept: Powers with Negative Exponents
Is there an error in this question or solution?
APPEARS IN
Advertisement Remove all ads
Advertisement Remove all ads
