Sum
Find the value of x, if `|(x, -1, 2),(2x, 1, -3),(3, -4, 5)|` = 29
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Solution
`|(x, -1, 2),(2x, 1, -3),(3, -4, 5)|` = 29
∴ `x|(1, -3),(-4, 5)| -(-1) |(2x, -3),(3, 5)| + 2 |(2x, 1),(3, -4)|` = 29
∴ x(5 – 12) + 1(10x + 9) + 2(– 8x –3) = 29
∴ – 7x + 10x + 9 – 16x – 6 = 29
∴ – 13x + 3 = 29
∴ – 13x = 26
∴ x = – 2
Concept: Determinants
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