Answer 1

`cot theta/(tan(90^circ - theta)) + (cos(90^circ - theta) tantheta sec(90^circ - theta))/(sin(90^circ - theta)cot(90^circ - theta)"cosec"(90^circ - theta))`

= `cot theta/cot theta + (sin theta* tan theta xx "cosec" theta)/(cos theta xx tan theta * sec theta)`

= `1 + sin theta/cos theta xx 1/sintheta xx costheta/1`

= 1 + 1

= 2