Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 10th
Advertisement Remove all ads

Find the value of ‘a’, if the line through (–2, 3) and (8, 5) is perpendicular to y = ax + 2 - Mathematics

Sum

Find the value of ‘a’, if the line through (– 2, 3) and (8, 5) is perpendicular to y = ax + 2

Advertisement Remove all ads

Solution

Given points are (– 2, 3) and (8, 5)

Slope of a line = `(y_2 - y_1)/(x_2 - x_1)`

= `(5 - 3)/(8 + 2)`

= `2/10`

= `1/5`

Slope of a line y = ax + 2 is “a”

Since two lines are ⊥r

m1 × m2 = – 1

`1/5 xx "a"` = – 1

⇒ `"a"/5` = – 1

⇒ a = – 5

∴ The value of a = – 5

Concept: Straight Line
  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

Samacheer Kalvi Mathematics Class 10 SSLC Tamil Nadu State Board
Chapter 5 Coordinate Geometry
Exercise 5.3 | Q 5 | Page 229
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×