Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 10th

# Find the value of ‘a’, if the line through (–2, 3) and (8, 5) is perpendicular to y = ax + 2 - Mathematics

Sum

Find the value of ‘a’, if the line through (– 2, 3) and (8, 5) is perpendicular to y = ax + 2

#### Solution

Given points are (– 2, 3) and (8, 5)

Slope of a line = (y_2 - y_1)/(x_2 - x_1)

= (5 - 3)/(8 + 2)

= 2/10

= 1/5

Slope of a line y = ax + 2 is “a”

Since two lines are ⊥r

m1 × m2 = – 1

1/5 xx "a" = – 1

⇒ "a"/5 = – 1

⇒ a = – 5

∴ The value of a = – 5

Concept: Straight Line
Is there an error in this question or solution?

#### APPEARS IN

Samacheer Kalvi Mathematics Class 10 SSLC Tamil Nadu State Board
Chapter 5 Coordinate Geometry
Exercise 5.3 | Q 5 | Page 229