# Find the sum to n terms 0.4 + 0.44 + 0.444 + ... - Mathematics and Statistics

Sum

Find the sum to n terms 0.4 + 0.44 + 0.444 + ...

#### Solution

Sn = 0.4 + 0.44 + 0.444 + … upto n terms

= 4(0.1 + 0.11 + 0.111 + …. upto n terms)

= 4/9 (0.9 + 0.99 + 0.999 + ... upto n terms)

= 4/9 [(1 − 0.1) + (1 − 0.01) + (1 − 0.001) ... upto n terms]

= 4/9 [(1 + 1 + 1 ... n times) − (0.1 + 0.01 + 0.001 + ... upto n terms)]

But 0.1, 0.01, 0.001, … n terms are in G.P.

with a = 0.1, r = 0.01/0.1 = 0.1

∴ Sn = 4/9{"n" - 0.1[(1 - (0.1)^"n")/(1 - 0.1)]}

∴ Sn = 4/9 {"n" - 0.1/0.9 [1 - (0.1)^"n"]}

∴ Sn = 4/9 ["n" - 1/9 (1 - (0.1)^"n")]

∴ Sn = 4/81 {9"n" - (1 - 1/10^"n")}

Is there an error in this question or solution?

#### APPEARS IN

Balbharati Mathematics and Statistics 2 (Arts and Science) 11th Standard Maharashtra State Board
Chapter 2 Sequences and Series
Exercise 2.2 | Q 6. (i) | Page 31