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Sum
Find the sum of those integers from 1 to 500 which are multiples of 2 as well as of 5.
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Solution
Same as part (i)
But multiples of 2 as well as 5 from 1 to 500 is 10, 20, 30,…, 500.
∴ a = 10, d = 10, an = l = 500
∵ an = a + (n – 1)d = 1
⇒ 500 = 10 + (n – 1)10
⇒ 490 = (n – 1) 10
⇒ n – 1 = 49
⇒ n = 50
∵ `S_n = n/2(a + 1)`
⇒ `S_50 = 50/2(10 + 500) = 50/2 xx 510`
= 50 × 255
= 12750
Concept: Sum of First n Terms of an A.P.
Is there an error in this question or solution?