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Find the Pythagorean triplet from among the following set of numbers.

9, 40, 41

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#### Solution

It is known that, if in a triplet of natural numbers, the square of the biggest number is equal to the sum of the squares of the other two numbers, then the three numbers form a Pythagorean triplet.

The given set of numbers is (9, 40, 41).

The biggest number among the given set is 41.

9^{2} = 81; 40^{2} = 1600; 41^{2} = 1681

Now, 81 + 1600 = 1681

∴ 9^{2} + 40^{2} = 41^{2}

Thus, (9, 40, 41) forms a Pythagorean triplet.

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