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Find the Pythagorean triplet from among the following set of numbers.

4, 7, 8

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#### Solution

It is known that, if in a triplet of natural numbers, the square of the biggest number is equal to the sum of the squares of the other two numbers, then the three numbers form a Pythagorean triplet.

The given set of numbers is (4, 7, 8).

The biggest number among the given set is 8.

8^{2} = 64; 7^{2} = 49; 4^{2} = 16

Now, 16 + 49 = 65 ≠ 64

∴ 4^{2} + 7^{2} ≠ 8^{2}

Thus, (4, 7, 8) does not form a Pythagorean triplet.

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