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Sum
Find the number of permutations of letters of the following word: SHANTARAM
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Solution
The word SHANTARAM has 9 letters of which ‘A’ is repeated 3 times and the rest all are different.
Hence, the number of permutations
= `("n"!)/("p"!)`
= `(9!)/(3!)`
= `(9 xx 8 xx 7 xx 6 xx 5 xx 4 xx 3!)/(3!)`
= 60480
Concept: Permutations - Permutations When All Objects Are Distinct
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Chapter 6: Permutations and Combinations - Exercise 6.4 [Page 82]