Find the middle term in the expansion of (2ax-bx2)12. - Mathematics

Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads
Sum

Find the middle term in the expansion of `(2ax - b/x^2)^12`.

Advertisement Remove all ads

Solution

Since the power of binomial is even, it has one middle term which is the `(12 + 2)^"th"/2` term and it is given by

T7 = `""^12"C"_6  (2ax)^6  ((-b)/x^2)^6`

= `""^12"C"_6  (2^6 a^6 x^6 * (-b)^6)/x^12`

= `""^12"C"_6  (2^6 a^6 b^6)/x^6`

= `(59136a^6b^6)/x^6`

Concept: General and Middle Terms
  Is there an error in this question or solution?
Chapter 8: Binomial Theorem - Solved Examples [Page 134]

APPEARS IN

NCERT Mathematics Exemplar Class 11
Chapter 8 Binomial Theorem
Solved Examples | Q 8 | Page 134

Video TutorialsVIEW ALL [1]

Share
Notifications

View all notifications


      Forgot password?
View in app×