# Find the middle term in the expansion of (2ax-bx2)12. - Mathematics

Sum

Find the middle term in the expansion of (2ax - b/x^2)^12.

#### Solution

Since the power of binomial is even, it has one middle term which is the (12 + 2)^"th"/2 term and it is given by

T7 = ""^12"C"_6  (2ax)^6  ((-b)/x^2)^6

= ""^12"C"_6  (2^6 a^6 x^6 * (-b)^6)/x^12

= ""^12"C"_6  (2^6 a^6 b^6)/x^6

= (59136a^6b^6)/x^6

Concept: General and Middle Terms
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#### APPEARS IN

NCERT Mathematics Exemplar Class 11
Chapter 8 Binomial Theorem
Solved Examples | Q 8 | Page 134

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