# Find the length of the intercept, cut off by the plane 2x + y − z = 5 on the x-axis - Mathematics

Sum
Find the length of the intercept, cut off by the plane 2x + y − z = 5 on the x-axis

#### Solution

The given plane is  2x + y - x = 5
Dividing both sides of the equation by 5, we obtain

2/5"x" + "y"/5 - "z"/5 = 1

⇒ "x"/(5/2) + "y"/5 + "z"/(-5) = 1

It is known that the equation of a plane in intercept form is "x"/"a" + "y"/"b" + "z"/"c" = 1, where a, b, c are the intercepts cut off by the plane at x, y, and z axes respectively.

Therefore, for the given equation, the intercept made with the x-axis is 5/2.

Is there an error in this question or solution?