Advertisement Remove all ads

Find the feasible solution of the following inequation: 3x + 2y ≤ 18, 2x + y ≤ 10, x ≥ 0, y ≥ 0 - Mathematics and Statistics

Chart
Graph

Find the feasible solution of the following inequation:

3x + 2y ≤ 18, 2x + y ≤ 10, x ≥ 0, y ≥ 0

Advertisement Remove all ads

Solution

Given inequalities 3x + 2y ≤ 18 2x + y ≤ 10
Corresponding equalities 3x + 2y = 18 2x + y = 10
Intersection of line with X-axis A(6, 0) C(5, 0)
Intersection of line with Y-axis B(0, 9) D(0, 10)
Origin test

3(0) + 2(0) ≤ 18

i.e., 0 ≤ 18

which is true

2(0) + 0 ≤ 10

i.e., 0 ≤ 10

which is true

Region Origin side of the line Origin side of the line

x ≥ 0, y ≥ 0 represent 1st quadrant.

The shaded portion represents the feasible solution.

Concept: Linear Programming Problem (L.P.P.)
  Is there an error in this question or solution?
Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×