Find the feasible solution of the following inequation:
2x + 3y ≤ 6, x + y ≥ 2, x ≥ 0, y ≥ 0
First we draw the lines AB and CB whose equations are 2x + 3y = 6 and x + y = 2 respectively.
|Line||Equation||Points on the X-axis||Points on the Y-axis||Sign||Region|
|AB||2x + 3y = 6||A (3,0)||B (0,2)||≤||origin side of line AB|
|CB||x + y = 2||C (2,0)||D(0,2)||≥||non -origin side of line CB|
The feasible solution is Δ ABC which is shaded in the graph.
Concept: Linear Programming Problem (L.P.P.)
Is there an error in this question or solution?