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Sum
Find the expected value, variance, and standard deviation of the random variable whose p.m.f.’s are given below :
x = x | 0 | 1 | 2 | 3 | 4 | 5 |
P (X = x) | `1/32` | `5/32` | `10/32` | `10/32` | `5/32` | `1/32` |
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Solution
We construct the following table to find the expected value, variance and standard deviation:
xi | P (xi) | xi·P (xi) | xi 2·P (xi) = xi × xi·P (xi) |
0 | `1/32` | 0 | 0 |
1 | `5/32` | `5/32` | `5/32` |
2 | `10/32` | `20/32` | `40/32` |
3 | `10/32` | `30/32` | `90/32` |
4 | `5/32` | `20/32` | `80/32` |
5 | `1/32` | `5/32` | `25/32` |
Total | `32/32` | `80/32` | `240/32` |
From the table,
∑ xi . P (xi) = `80/32 = 5/2` ,
∑ xi2 . P ( xi) = `240/32 = 15/2`
Expected value = E (X) = ∑ xi . P (xi)
= `5/2` = 2.5
Variance = V(x) = ∑ xi2 . P (xi) - [ ∑ xi·P (xi) ]2
= `15/2 - (5/2)^2`
= `15/2 - 25/4`
= `30/4 - 25/4`
= `5/4`
= 1.25
Standard deviation = `sqrt(V(X)) = sqrt 1.25`
= 1.118
Concept: Variance of a Random Variable
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