Question

Find the equation of the straight line parallel to 5x − 4y + 3 = 0 and having x-intercept 3

Answer 1

The equation of any line parallel to 5x – 4y + 3 = 0 is

5x – 4y + k = 0 ........(1)

The x-intercept of line (I) is obtained by putting

y = 0 in the equation (1)

⇒ 5x – 4(0) + k = 0

5x = – k

⇒ x = `- "k"/5`

Given that the x-intercept in 3

∴ `- "k"/5` = 3

⇒ k = – 15

∴ The equation of the required line is

5x – 4y – 15 = 0