# Find the equation of the hyperbola referred to its principal axes: whose length of conjugate axis = 12 and passing through (1, – 2) - Mathematics and Statistics

Sum

Find the equation of the hyperbola referred to its principal axes:

whose length of conjugate axis = 12 and passing through (1, – 2)

#### Solution

Let the equation of the hyperbola referred to principal axes be x^2/"a"^2 - y^2/"b"^2 = 1    ...(1)

Length of conjugate axes = 2b = 12

∴ b = 6

The hyperbola passes through (1, – 2)

∴ 1^2/"a"^2 - (-2)^2/6^2 = 1 ........[∵ b = 6]

∴ 1/"a"^2 = 1 + 1/9 = 10/9

∴ a2 = 9/10

∴ by (1), the equation of the required hyperbola is x^2/((9/10)) - y^2/36 = 1

∴ (10x^2)/9 - y^2/36 = 1.

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