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Sum

Find the distance of (4, - 2, 6) from each of the following:

(a) The XY-plane

(b) The YZ-plane

(c) The XZ-plane

(d) The X-axis

(e) The Y-axis

(f) The Z-axis.

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#### Solution

Let the point A be (4, - 2, 6).

Then,

(a) The distance of A from XY-plane = |z| = 6

(b) The distance of A from YZ-plane = |x| = 4

(c) The distance of A from ZX-plane = |y| = 2

(d) The distance of A from X-axis

`= sqrt("y"^2 + "z"^2) = sqrt((-2)^2 + 6^2) = sqrt40 = 2sqrt10`

(e) The distance of A from Y-axis

`sqrt("z"^2 + "x"^2) = sqrt(6^2 + 4^2) = sqrt52 = 2sqrt13`

(f) The distance of A from Z-axis

`= sqrt("x"^2 + "y"^2) = sqrt(^2 + (-2)^2) = sqrt20 = 2sqrt5`

Concept: Vectors and Their Types

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