Sum
Find the direction ratios of a vector perpendicular to the two lines whose direction ratios are 1, 3, 2 and –1, 1, 2
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Solution
Let L1 and L2 be the two lines with direction ratios 1, 3, 2 and –1, 1, 2 respectively.
Let the direction ratios of the vector perpendicular to L1 and L2 be a, b, c.
∴ a + 3b + 2c = 0
and −a + b + 2c = 0
∴ `"a"/|(3, 2),(1, 2)| = (-"b")/|(1, 2),(-1, 2)| = "c"/|(1, 3),(-1, 1)|`
∴ `"a"/(6 - 2) = (-"b")/(2 + 2) = "c"/(1 + 3)`
∴ `"a"/4 = (-"b")/4 = "c"/4`
∴ The direction ratios of the vector are 4, – 4, 4.
Concept: Vector Product of Vectors (Cross)
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