Sum

Find the coordinates of point A, where AB is a diameter of the circle with centre (–2, 2) and B is the point with coordinates (3, 4).

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#### Solution

Let the centre of the circle be O.

Since AB is the diameter so, O is the midpoint of AB.

Thus, using the section formula,

`(a+3)/(2) = - 2`

⇒ `a = -4 - 3 = -7`

And

`(b + 4)/(2) = 2`

⇒ `b = 4 - 4 = 0`

So, the coordinate of point A is (-7,0).

Concept: Coordinate Geometry

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