# Find the change in length of a second’s pendulum, if the acceleration due to gravity at the place changes from 9.75 m/s2 to 9.8 m/s2. - Physics

Sum

Find the change in length of a second’s pendulum, if the acceleration due to gravity at the place changes from 9.75 m/s2 to 9.8 m/s2.

#### Solution

Data: gf =9.75 m/s2 , g2 = 9.8 m/s2

Length of a seconds pendulum, L = "g"/π^2

∴ L1 = "g"_1/"π"^2=9.75/9.872 = 0.9876 m

and L2 = "g"_2/π^2=9.8/9.872 = 0.9927 m

∴ The length of the second's pendulum must be increased from 0.9876 m to 0.9927 m, i.e., by 0.0051 m.

Concept: Acceleration (A), Velocity (V) and Displacement (X) of S.H.M.
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#### APPEARS IN

Balbharati Physics 12th Standard HSC Maharashtra State Board
Chapter 5 Oscillations
Exercises | Q 15 | Page 130