Question

Find the area of the triangle whose vertices are (–8, 4), (–6, 6) and (–3, 9).

Answer 1

Given vertices are:

(x₁, y₁) = (– 8, 4)

(x₂, y₂) = (– 6, 6)

(x₃, y₃) = (– 3, 9)

Area of triangle = `1/2 (x_1(y_₂ - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2))`

= `1/2 (-8(6 - 9) + -6(9 - 4) + -3(4 - 6))`

= `1/2 (-8(-3) + -6(5) + -3(-2))`

= `1/2 (24 - 30 + 6)`

= `1/2 (30 - 30)`

= 0 units.