Find the area of the shaded field shown in figure.
In a figure, join ED
From figure, radius of semi-circle DEF, r = `6 - 4` = 2 m
Now, area of rectangle ABCD = `BC xx AB = 8 xx 4 = 32 cm^2`
And area of semi-circle DFE = `(pir^2)/2 = pi/2 (2)^2 = 2pi m^2`
∴ Area of shaded region = Area of rectangle ABCD + Area of semi-circle DFE
= `(32 + 2pi) m^2`
Concept: Areas of Combinations of Plane Figures
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