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Sum
Find the area of the right-angled triangle with hypotenuse 40 cm and one of the other two sides 24 cm.
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Solution
In right angled triangle ABC Hypotenuse AC = 40 cm
One side AB = 24 cm
∴ BC = `sqrt("AC"^2 - "AB"^2)`
= `sqrt(40^2 - 24^2) = sqrt(1600 - 576)`
= `sqrt(1024) = 32` cm
∴ Area = `1/2 "AB" xx "BC" = 1/2 xx 24 xx 32 "cm"^2 = 384 "cm"^2`
Concept: Perimeter of Triangles
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