Question

Find the area of the right-angled triangle with a hypotenuse of 40 cm and one of the other two sides of 24 cm.

Answer 1

by applying Pythagoras' theorem,

H² = P² + B²

40² = P² + 24²

P² = 40² - 24²

= (40 - 24) (40 + 24)

= 16 × 64 = 1024 cm²

P = `sqrt1024 = 32` cm

A = `1/2 xx  "b" xx "h"`

= `1/2 xx 24 xx 32`

= `12 xx 32`

= 384 cm²