Question

Find the area of the right-angled triangle with hypotenuse 40 cm and one of the other two sides 24 cm.

Answer 1

In right angled triangle ABC Hypotenuse AC = 40 cm
One side AB = 24 cm

∴ BC = `sqrt("AC"^2 - "AB"^2)`

= `sqrt(40^2 - 24^2) = sqrt(1600 - 576)`

= `sqrt(1024) = 32` cm

∴ Area = `1/2  "AB" xx "BC" = 1/2 xx 24 xx 32  "cm"^2 = 384  "cm"^2`