Question

Find the area of the flower bed (with semi-circular ends) shown in figure.

Answer 1

Length and breadth of the rectangular portion AFDC of the flower bed are 38 cm and 10 cm.

Area of the flower bed = Area of the rectangular portion + Area of the two semicircles.

Area of rectangle AFDC = Length × Breadth

= 38 × 10

= 380 cm²

Both ends of flower bed are semi-circle in shape.

Diameter of the semi-circle = Breadth of the rectangle AFDC = 10 cm

Radius of the semi-circle = `10/2` = 5 cm

Area of the semi-circle = `(pir^2)/2`

= `25(pi/2)  cm^2`

As, there are two semi-circles in the flower bed,

Area of two semi-circles = `2 xx ((pir^2)/2)`

= `25 pi  cm^2`

Therefore, total area of flower bed = `(380 + 25pi)  cm^2`.