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Find the Area of a Triangle, Whose Sides Are : 10 Cm, 24 Cm, and 26 Cm - Mathematics

Sum

Find the area of a triangle, whose sides are :

10 cm, 24 cm, and 26 cm

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Solution

Sides of ∆ are
a = 10 cm
b = 24 cm
c = 26 cm

S = `(a + b + c)/2 = (10 + 24 + 26)/2`

= `60/2 = 30`

area of Δ = `sqrt(S(S - a)(S - b)(S - c))`

= `sqrt(30(30 - 10)(30 - 24)(30 - 26))`

= `sqrt(30 xx 20 xx 6 xx 4)`

= `sqrt(10 xx 3 xx 10 xx 2 xx 2 xx 3 xx 2 xx 2)`

= `sqrt(10 xx 10 xx 3 xx 3 xx 2 xx 2 xx 2 xx 2)`

= `10 xx 3 xx 2 xx 2 = 120  "cm"^2`

Concept: Perimeter of Triangles
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APPEARS IN

Selina Concise Mathematics Class 8 ICSE
Chapter 20 Area of a Trapezium and a Polygon
Exercise 20 (A) | Q 1.1 | Page 223
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