Find the Amount and the Compound Interest on ₹ 10,000 in 3 Years, If the Rates of Interest for the Successive Years Are 10%, 15%, and 20% Respectively. - Mathematics


Find the amount and the compound interest on ₹ 10,000 in 3 years, if the rates of interest for the successive years are 10%, 15%, and 20% respectively.



Principal (P) = ₹10,000

Time (t) = 3 years

Rate (R1) = 10%

Rate (R2) = 15%

Rate (R3) = 20%

Amount =`"P"xx(1+"R"_1/100)(1+"R"_2/100)(1+"R"_3/100)`



= ₹15,180

C.I. = Amount − Principal

= ₹15,180 − ₹10,000

= ₹5180

  Is there an error in this question or solution?
Chapter 9: Interest - Exercise 9 (C) [Page 115]


Selina Concise Mathematics Class 8 ICSE
Chapter 9 Interest
Exercise 9 (C) | Q 26 | Page 115


The population of a place increased to 54000 in 2003 at a rate of 5% per annum find the population in 2001

Compute the amount and the compound interest in  the following by using the formulae when:
Principal = Rs 12800, Rate = \[7\frac{1}{2} %\], Time = 3 years

Compute the amount and the compound interest in  the following by using the formulae when:
Principal = Rs 160000, Rate = 10 paise per rupee per annum compounded half-yearly, Time = 2 years.

The count of bacteria in a culture grows by 10% in the first hour, decreases by 8% in the second hour and again increases by 12% in the third hour. If the count of bacteria in the sample is 13125000, what will be the count of bacteria after 3 hours?

The population of a certain city was 72000 on the last day of the year 1998. During next year it increased by 7% but due to an epidemic it decreased by 10% in the following year. What was its population at the end of the year 2000?

The value of a machine depreciates at the rate of 10% per annum. What will be its value 2 years hence, if the present value is Rs 100000? Also, find the total depreciation during this period.

Pritam bought a plot of land for Rs 640000. Its value is increasing by 5% of its previous value after every six months. What will be the value of the plot after 2 years?

Sameerrao has taken a loan of ₹12500 at a rate of 12 p.c.p.a. for 3 years. If the interest is compounded annually then how many rupees should he pay to clear his loan?

To start a business Shalaka has taken a loan of ₹8000 at a rate of 10 `1/2` p.c.p.a. After two years how much compound interest will she have to pay?

On the construction work of a flyover bridge there were 320 workers initially. The number of workers were increased by 25% every year. Find the number of workers after 2 years.

A shepherd has 200 sheep with him. Find the number of sheep with him after 3 years if the increase in the number of sheep is 8% every year.

In a forest there are 40,000 trees. Find the expected number of trees after 3 years if the objective is to increase the number at the rate 5% per year.

The cost price of a machine is 2,50,000. If the rate of depreciation is 10% per year find the depreciation in price of the machine after two years.

Find the compound interest if the amount of a certain principal after two years is ₹ 4036.80 at the rate of 16 p.c.p.a.

A principal amounts to ₹13924 in 2 years by compound interest at 18 p.c.p.a. Find the principal.

The population of a suburb is 16000. Find the rate of increase in the population if the population after two years is 17640.

Find the difference between simple interest and compound interest on ₹20000 at 8 p.c.p.a.

Gautam takes a loan of ₹ 16,000 for 2 years at 15% p.a. compound interest. He repays ₹ 9,000 at the end of the first year. How much must he pay at the end of the second year to clear the debt?

Find the amount and the compound interest on ₹ 4,000 in 2 years, if the rate of interest for the first year is 10% and for the second year is 15%.

A TV was bought at a price of ₹ 21,000. After one year the value of the TV was depreciated by 5% (Depreciation means reduction of value due to use and age of
the item). Find the value of the TV after one year.

The cost of a sewing machine is Rs 7,000. Its value depreciates at 8% p.a. Then the value of the machine after 2 years is Rs 5,924.80.

The population of a town was decreasing every year due to migration, poverty and unemployment. The present population of the town is 6,31,680. Last year the migration was 4% and the year before last, it was 6%. What was the population two years ago?


      Forgot password?
Use app×