Find the term t15 of an A.P. : 4, 9, 14, …………..

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#### Solution

We need to find the 15th term of the A.P., 4, 9, 14

Here, the initial term is, a = 4.

Common difference = 14 - 9 = 9 - 4 = 5

The general term of an A.P is given by the formula,

t_{n} = a + (n - 1)d

t_{15} = 4 + (15 - 1) × 5

t_{15} = 4 + 14 × 5

t_{15} = 4 + 70

t_{15} = 74

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