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Find the Surface Area of a Cuboid Whose Length = 6 Dm, Breadth = 8 Dm, Height = 10 Dm. - Mathematics

Answer in Brief

Find the surface area of a cuboid whose length = 6 dm, breadth = 8 dm, height = 10 dm.

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Solution

\[\text { Dimensions of the cuboid: }\]

\[\text{ Length = 6 dm } \]

\[\text { Breadth = 8 dm } \]

\[\text { Height = 10 dm } \]

\[\text { Surface area of the cuboid  }= 2 \times (\text { length } \times \text { breadth + breadth } \times \text { height + length }\times\text {  height })\]

\[ = 2 \times (6 \times 8 + 8 \times 10 + 6 \times 10)\]

\[ = 2 \times (48 + 80 + 60)\]

\[ = 376 {dm}^2 \]

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APPEARS IN

RD Sharma Class 8 Maths
Chapter 21 Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube)
Exercise 21.3 | Q 1.2 | Page 22
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