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Find the sums given below : 34 + 32 + 30 + . . . + 10 - Mathematics

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Question

Find the sums given below :

34 + 32 + 30 + . . . + 10

Solution

34 + 32 + 30 + ……….. + 10

For this A.P.,

a = 34

d = a2 − a1 = 32 − 34 = −2

l = 10

Let 10 be the nth term of this A.P.

l = a + (− 1) d

10 = 34 + (n − 1) (−2)

−24 = (− 1) (−2)

12 = n − 1

n = 13

`S_n = n/2(a+1)`

`=13/2(34+10)`

`=(13xx44)/2 = 13 xx 22`

= 286

  Is there an error in this question or solution?
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APPEARS IN

 NCERT Solution for Mathematics Textbook for Class 10 (2019 (Latest))
Chapter 5: Arithmetic Progressions
Ex. 5.3 | Q: 2.2 | Page no. 112
 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 5: Arithmetic Progression
Ex. 5.6 | Q: 13.6 | Page no. 51
 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 5: Arithmetic Progression
Ex. 5.6 | Q: 13.6 | Page no. 51
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Solution Find the sums given below : 34 + 32 + 30 + . . . + 10 Concept: Sum of First n Terms of an AP.
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