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Find the sums given below : 34 + 32 + 30 + . . . + 10 - Mathematics

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Find the sums given below :

34 + 32 + 30 + . . . + 10

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Solution

34 + 32 + 30 + ……….. + 10

For this A.P.,

a = 34

d = a2 − a1 = 32 − 34 = −2

l = 10

Let 10 be the nth term of this A.P.

l = a + (− 1) d

10 = 34 + (n − 1) (−2)

−24 = (− 1) (−2)

12 = n − 1

n = 13

`S_n = n/2(a+1)`

`=13/2(34+10)`

`=(13xx44)/2 = 13 xx 22`

= 286

Concept: Sum of First n Terms of an AP
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APPEARS IN

NCERT Class 10 Maths
Chapter 5 Arithmetic Progressions
Exercise 5.3 | Q 2.2 | Page 112
RD Sharma Class 10 Maths
Chapter 5 Arithmetic Progression
Exercise 5.6 | Q 13.6 | Page 51
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