# Find the sum of all natural numbers between 250 and 1000 which are exactly divisible by 3 - Mathematics

Sum

Find the sum of all natural numbers between 250 and 1000 which are exactly divisible by 3

#### Solution

Clearly, the numbers between 250 and 1000 which are divisible by 3 are 252, 255, 258, …., 999.

This is an A.P. with first term a = 252, common difference = 3 and last term = 999.

Let there be n terms in this A.P. Then,

⇒ an = 999

⇒ a + (n – 1)d = 999

⇒ 252 + (n – 1) × 3 = 999 ⇒ n = 250

∴ Required sum = S_n = \frac { n }{ 2 } [a + l]

= \frac { 250 }{ 2 } [252 + 999] = 156375

Concept: Sum of First n Terms of an AP
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