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Find the square root of:

\[38\frac{11}{25}\]

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#### Solution

We know:

\[\sqrt{38\frac{11}{25}} = \sqrt{\frac{961}{25}} = \frac{\sqrt{961}}{\sqrt{25}}\]

Now, let us compute the square roots of the numerator and the denominator separately.

\[\sqrt{961} = 31\]

\[\sqrt{25} = 5\]

\[ \therefore \sqrt{38\frac{11}{25}} = \frac{31}{5}\]

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