# Find the Rms Value of the Waveform Given Below:- - Basic Electrical and Electronics Engineering

Sum

Find the RMS value of the waveform given below:-

#### Solution

The rms value of the alternating current is given by,

"Irms"=sqrt(1/(t_2-t_1)int_(t_1)^(t_2)i^2(t)dt

t_1="T"      t_2=2"T"   i=I_msinthetat

"Irms"=sqrt(1/(2"T"-"T")int_"T"^(2"T")("I"_msinvarphit)^2("T")dt)="I"_msqrt(int_"T"^(2"T")sin^2thetatdt)="I"_msqrt([theta/2-(sin2theta)/4]_"T"^(2"T")

"Irms"="I"_msqrt[(2"T")/2-(sin4"T")/4-"T"/2+(sin2"T")/4]

"Irms"="I"_msqrt("T"/2-(sin4"T")/4+(sin2"T")/4)

Concept: RMS and Average Value
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