Answer 1

Let p(x) = x³ + 3x² + 3x + 1

x + π = 0 ⇒ x = -π

∴ Remainder = (-π)³ + 3(-π)² - 3(-π) + 1

                   = -π³ + 3π² - 3π + 1

Therefore, the remainder is -π³ + 3π² - 3π + 1.

Answer 2

By long division,

Therefore, the remainder is -π³ + 3π² - 3π + 1.