Maharashtra State BoardSSC (English Medium) 9th Standard
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Find the Reduced Form of the Ratio of the First Quantity to Second Quantity. - Algebra

Sum

Find the reduced form of the ratio of the first quantity to second quantity.
14 rs, 12 rs. 40 paise

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Solution

14 rupees = 1400 p
12 rupees 40 paise = 1200 + 40 = 1240 p
∴ 14 rupees : 12 rupees 40 paise = 1400 p : 1240 p = `(14000 ÷ 40) /(1240 ÷ 40) = 35/31 = 35 : 31`                                                                                 ........ (HCF of 1400 and 1240 = 40)

Concept: Properties of Ratio
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APPEARS IN

Balbharati Mathematics 1 Algebra 9th Standard Maharashtra State Board
Chapter 4 Ratio and Proportion
Practice Set 4.1 | Q 2.2 | Page 61
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